49x^2+48=98x

Solution for 49x^2+48=98x equation:

49x^2+48=98x

We move all terms to the left:

49x^2+48-(98x)=0

a = 49; b = -98; c = +48;
Δ = b2-4ac
Δ = -982-4·49·48
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-14}{2*49}=\frac{84}{98}
=6/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+14}{2*49}=\frac{112}{98}
=1+1/7
$